SOLUTION: A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)      Log On


   

Question 1153238: A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)
Found 3 solutions by josgarithmetic, MathLover1, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
X, the number

X%2BX%2F5%2BX%2F6=82
.
.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let a number be x
1%2F5+of that number is x%2F5
1%2F6 of that number is x%2F6
if they are added, we have x%2F5%2Bx%2F6
if the result is 82, we have x%2F5%2Bx%2F6=82
to find the original number, solve
x%2F5%2Bx%2F6=82
6x%2F%286%2A5%29%2B5x%2F%285%2A6%29=82
6x%2F30%2B5x%2F30=82.....both sides multiply by 30
30%286x%2F30%29%2B30%285x%2F30%29=82%2A30
6x%2B5x=2460
11x=2460
x=2460%2F11=> exact solution

check:
x%2F5%2Bx%2F6=82
%282460%2F11%29%2F5%2B%282460%2F11%29%2F6=82
2460%2F55%2B2460%2F66=82
44.72727272727272%2B37.27272727272727=82
82=82


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)
Algebra:        With number being N, equation to be solved: matrix%281%2C3%2C+N+%2B+N%2F5+%2B+N%2F6%2C+%22=%22%2C+82%29

Pre-Algebra:    

                The number, with the same denominator as the above fraction, is represented by 1, or fraction   

                We now see that: , and so, the number MUST BE: 

IGNORE the OTHER PERSON'S RESPONSE, as it is SENSELESS!!