SOLUTION: Hi can you please help me this problem. Richard was driving his van and stopped for gas when the gas tank was 1/8 full. He bought 25 litres of gas for $50. Then, he noticed that

Algebra ->  Finance -> SOLUTION: Hi can you please help me this problem. Richard was driving his van and stopped for gas when the gas tank was 1/8 full. He bought 25 litres of gas for $50. Then, he noticed that      Log On


   

Question 1153176: Hi can you please help me this problem.
Richard was driving his van and stopped for gas when the gas tank was 1/8 full. He bought 25 litres of gas for $50. Then, he noticed that the tank was only 3/4 full, so he filled it completely. How much did Richard pay in total.
Thanks
Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

3%2F4  of the tank volume minus  1%2F8  of the tank volume is  


    3%2F4 - 1%2F8 = 6%2F8-1%2F8 = 5%2F8  of the tank volume.


For  5%2F8  of the tank volume he payed 50 dollars, i.e. 10 dollars for each 1%2F8 of the tank volume.


Since he filled, finally,  7%2F8  of the tank volume, he payed 10*7 = 70 dollars, in all, at the gas station.   ANSWER

Solved.

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Notice that in my solution,  the given data of  25  liters is  EXCESSIVE.

I solved the problem and got the answer without using this number.

So,  it is  UNNECASSARY  in this problem (!)