SOLUTION: If log3(x+1)-log3(x-1)=2, then x=A/8 where A=

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Question 115302: If log3(x+1)-log3(x-1)=2, then x=A/8 where A=
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If log3(x+1)-log3(x-1)=2, then x=A/8 where A=
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The base is "3, so:
log[(x+1)/(x-1)] = 2
[(x+1)/(x-1)] = 3^2
x+1 = 9x-9
8x = 10
x = 5/4
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If x = A/8
then (5/4) = A/8
A = 10
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Cheers,
Stan H.