SOLUTION: A tank can be filled by a pipe in 2.0 h and emptied by another pipe in 3.0h. How much time will be required to fill an empty tank if both are running?

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Question 1152897: A tank can be filled by a pipe in 2.0 h and emptied by another pipe in 3.0h. How much time will be required to fill an empty tank if both are running?

Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
.

First pipe fills  1%2F2  of the tank volume each our.


Second pipe drains 1%2F3  of the tank volume each our.


The net inflow rate to the tank is the difference  1%2F2 - 1%2F3 = 3%2F6+-+2%2F6 = 1%2F6  of the tank volume per hour.


It means, that the tank be filled in 6 hours with two pipes working together.

Solved.

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It is a standard and typical joint work problem.

There is a wide variety of similar solved joint-work problems with detailed explanations in this site.  See the lessons
    - Using Fractions to solve word problems on joint work
    - Solving more complicated word problems on joint work
    - Selected joint-work word problems from the archive


Read them and get be trained in solving joint-work problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems"  of the section  "Word problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.