SOLUTION: Chris wants to resize a 4-inch by 6-inch photo by a factor of 4/3 what are the dimensions of the new photo?What is the answer?

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Question 1152836: Chris wants to resize a 4-inch by 6-inch photo by a factor of 4/3 what are the dimensions of the new photo?What is the answer?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.

Does Chris want to  INCREASE  or to  DECREASE  the photo  ?

The word  "resize"  itself does determine nothing . . .


So,  INFLATE  or  DEFLATE  ?



Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Question is a little unclear. Resize by area, or resize by linear dimensions?

If by AREA is meant, then
24%284%2F3%29=32 square inches

%284%2Bx%29%286%2Bx%29=32
x%5E2%2B10x%2B24=32
x%5E2%2B10x=8
x%5E2%2B10x-8=0

x=%28-10%2B-+sqrt%28100%2B4%2A8%29%29%2F2
x=%28-10%2B-+sqrt%28132%29%29%2F2
x=%28-10%2B-+2%2Asqrt%2833%29%29%2F2
x=-5%2B-+sqrt%2833%29
highlight_green%28x=-5%2Bsqrt%2833%29%29
This x value is about 0.7446 inches.
Very nearly 3%2F4 inch increase in each dimension.

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New Width about 4%263%2F4 inches
New Length about 6%263%2F4 inches
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