SOLUTION: A committee of 6 U.S. senators is to be formed with 3 Democrats and 3 Republicans. In how many ways can this be done if there are 61 Democratic senators and 39 Republican senators?

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Question 1152786: A committee of 6 U.S. senators is to be formed with 3 Democrats and 3 Republicans. In how many ways can this be done if there are 61 Democratic senators and 39 Republican senators?
Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

We will use the combination function
C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29
to count the number of ways to select members. We use the combination function (not the permutation function) because order does not matter when selecting a committee. Any member does not outrank another, and there are no special positions. All that matters is the group as a whole rather an any particular individual.

Your book may use notation that looks like instead of C%28n%2Cr%29, but its the same thing.

The exclamation marks represent factorials. Writing something like 6%21 means 6%21+=+6%2A5%2A4%2A3%2A2%2A1 so we start at 6 and count our way down to 1 multiplying along the way.

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Note how something like 4%21+=+4%2A3%2A2%2A1 is fully contained inside of the expression for 6%21

This means,

In short, 6%21+=+6%2A5%2A4%21

This will come in handy later on. Specifically the lines where I write "use the factorial trick" (see below). This is to cancel out factorials that would otherwise be massively large numbers.

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For the Democrats, we have n = 61 people to choose from and r = 3 slots to fill.
Use the combination function to figure out how many ways there are to do this.

C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29

C%2861%2C3%29+=+%2861%21%29%2F%283%21%2A%2861-3%29%21%29 Replace n with 61, replace r with 3

C%2861%2C3%29+=+%2861%2A60%2A59%2A58%21%29%2F%283%21%2A58%21%29 Use the factorial trick. We started at 61 and stop at 58 because of the 58! in the denominator.

We have these highlighted terms pair up

C%2861%2C3%29+=+%2861%2A60%2A59%2Across%2858%21%29%29%2F%283%21%2Across%2858%21%29%29 and cancel out. A much simpler expression is left over

C%2861%2C3%29+=+%2861%2A60%2A59%29%2F%283%2A2%2A1%29 Expand out 3%21 to get 3%2A2%2A1

At this point, we have three numbers multiplied in the numerator. It is not a coincidence this lines up with r = 3. So another shortcut is to start with the number n = 61 and count down by 1 until you have r = 3 items to multiply out in the numerator. Then you divide over 3! = 3*2*1

Let's simplify

C%2861%2C3%29+=+%2861%2A60%2A59%29%2F%283%2A2%2A1%29

C%2861%2C3%29+=+215940%2F6

C%2861%2C3%29+=+35990

There are 35990 ways to pick the Democrats.

We'll use this number later, so let A = 35990

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Repeat for the Republicans

n = 39

r = 3

C%28n%2C+r%29+=+%28n%21%29%2F%28+r%21%2A%28n-r%29%21+%29

C%2839%2C+3%29+=+%2839%21%29%2F%28+3%21%2A%2839-3%29%21+%29

C%2839%2C+3%29+=+%2839%21%29%2F%28+3%21%2A36%21+%29

C%2839%2C+3%29+=+%2839%2A38%2A37%2A36%21%29%2F%28+3%21%2A36%21+%29 Use the factorial trick

Terms pair up

C%2839%2C+3%29+=+%2839%2A38%2A37%2Across%2836%21%29%29%2F%28+3%21%2Across%2836%21%29+%29 and cancel out

C%2839%2C+3%29+=+%2839%2A38%2A37%29%2F%28+3%21+%29 Since r = 3, we have 3 numbers multiplied in the numerator. We started at n = 39 and counted down by 1 each time.

C%2839%2C+3%29+=+%2839%2A38%2A37%29%2F%28+3%2A2%2A1+%29 Expand out 3%21 to get 3%2A2%2A1

C%2839%2C+3%29+=+%28+54834+%29%2F%28+6+%29

C%2839%2C+3%29+=+9139

Let B = 9139 represent the number of ways to pick the Republicans.
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To summarize what we found so far,
A = 35990 is the number of ways to pick the Democrats
B = 9139 is the number of ways to pick the Republicans

So,
A*B = 35990*9139 = 328,912,610 is the number of ways to pick the entire committee.
Order does not matter.
This number is very close to 329 million.

Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.

Usually, such problems are solved in three lines:

    There are  C%5B61%5D%5E3 = %2861%2A60%2A59%29%2F%281%2A2%2A3%29 = 35990 ways to select 3 democrats from 61 democrats.


    There are  C%5B39%5D%5E3 = %2839%2A38%2A37%29%2F%281%2A2%2A3%29 = 9139 ways to select 3 republicans from 39 republicans.


    These selections are independent; therefore, the final ANSWER is the product of these numbers  35990*9139 = 328912610.

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The symbols  C%5Bn%5D%5Ek  denote  combinations  of  "n"  items taken  "k"  at a time.

On Combinations,  see introductory lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.