SOLUTION: Find b and c so that y=16x^2+bx+c has vertex (−9,7)

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Question 1152745: Find b and c so that y=16x^2+bx+c has vertex (−9,7)
Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.

y = 16%2A%28x%2B9%29%5E2+%2B+7 = 16x^2 + 2*16*9x + 16*81 + 7 = 16x^2 + 288x + 1303.


    b = 288,  c = 1303.      ANSWER






Plot y = 16*(x+9)^2+7 (red) and y = 16x^2 + 288 + 1303 (green)


The two lines COINCIDE, therefore, you see only one of them (the green one, which overlays / over-poses the red line).


Solved.