SOLUTION: A bicyclist rode into the country for 5 h. In returning, her
speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
I don't know how to turn this in to an
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speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
I don't know how to turn this in to an
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Question 115268This question is from textbook Beginning Algebra
: A bicyclist rode into the country for 5 h. In returning, her
speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
I don't know how to turn this in to an equation. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! A bicyclist rode into the country for 5 h. In returning, her
speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
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Into the country DATA:
Time = 5 hrs ; Rate = x mph ; Distance = rt = 5x miles
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Return DATA:
Time = 4 hrs ; Rate = (x+5) mph ; Distance = rt = 4(x+5) miles
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EQUATION:
distance out = distance back
5x = 4(x+5)
5x = 4x+20
x = 20 mph (speed into the country)
x+5 = 25 mph (speed back)
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Cheers,
Stan H.
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