Question 1152469: 1) A bag contain 8 red balls and 5 white balls, 2 successive drawing of 3 balls are made such that
1) balls are replaced before the second trial
2) balls are not replaced before the second trial
find the probability that 1st drawing will give 3 white balls and 3 red balls
Answer by greenestamps(13209)   (Show Source):
You can put this solution on YOUR website!
To me at least, the wording of the problem is not clear. It talks about "drawings" and "trials", and I can't figure out whether those are two names for the same thing.
The way I read the problem, 3 balls are drawn ("1st drawing") and then 3 more balls are drawn ("2nd drawing"). And if that is the case, then of course the first drawing can't give 3 white balls and 3 red balls, because the first drawing only draws three balls....
So the probability that the 1st drawing will give 3 white balls and 3 red balls is 0.
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