SOLUTION: The perimeter of a rectangle is 70 and its diagonal is 25. Find its length and width. Its length is Its width is where length > width

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Question 1152451: The perimeter of a rectangle is 70 and its diagonal is 25. Find its length and width.
Its length is

Its width is
where length > width

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!


let the length be a and the with b
if the perimeter of a rectangle is 70, we have
2%28a%2Bb%29=70
a%2Bb=35
a=35-b

if its diagonal is 25, we have
d=25
diagonal divides rectangle into two right triangles

in one right triangle, one leg is the length a, the other leg is the width b
using Pythagorean theorem, we have:
d%5E2=a%5E2%2Bb%5E2....substitute a and d
25%5E2=%2835-b%29%5E2%2Bb%5E2.....solve for b
625=b%5E2+-+70+b+%2B+1225%2Bb%5E2
2b%5E2+-+70+b+%2B+1225-625=0
2b%5E2+-+70+b+%2B+600=0.....simplify
b%5E2+-+35+b+%2B+300=0
%28b+-+20%29+%28b+-+15%29+=+0
=>+b=20+or+b=15+
since b is width, go with b=15 and the other (20) will be the length a
or calculate:
a=35-15
a=20+
answer:
Its length is 20+
Its width is 15+
where length > width