SOLUTION: The length of a rectangular garden is 7 feet longer than its width. If the garden's perimeter is 178 feet, what is the area of the garden in square feet?

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Question 1152449: The length of a rectangular garden is 7 feet longer than its width. If the garden's perimeter is 178 feet, what is the area of the garden in square feet?
Answer by MathLover1(20850) About Me  (Show Source):
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let the length be L, and its width W
if the length of a rectangular garden is 7 feet longer than its width, we have
L=W%2B7.....eq.1
if the garden's perimeter is 178 feet, then
2%28L%2BW%29=178
L%2BW=178%2F2
L%2BW=89..........substitute L from eq.1
W%2B7%2BW=89
2W=89-7
2W=82
W=41 feet
go to
L=W%2B7.....eq.1, substitute W
L=41%2B7
L=48 feet

then, the area of the garden in square feet will be:
A=L%2AW
A=48%2A41
A=1968 square feet