Question 1152412:  A rectangular piece of cardboard, whose area is 396 square centimeters, is made into an open box by cutting a 2-centimeter square from each corner and turning up the sides. If the box is to have a volume of 504cubic centimeters, what size cardboard should you start with? 
 Answer by ikleyn(52901)      (Show Source): 
You can  put this solution on YOUR website! . 
Let x and y be the values under the question, i.e. dimensions of the original piece of cardboard.
The height of the box is 2 cm;
the area of the base of the box is equal to its volume divided by the height
    area of the base of the box =   = 252 cm^2.
It gives you your first equation
    (x-2*2)*(y-2*2) = 252,   or
    (x-4)*(y-4) = 252.       (1)
The second equation is for the surface area of the box
    (x-4)*(y-4) + 2*(x-4) + 2*(y-4) = 396 - 4*(2*2)  cm^2,   or
    (x-4)*(y-4) + 2*(x-4) + 2*(y-4) = 380.    (2)
It is your second equation.
Simplify them.
In the left side of (2),  replace  (x-4)*(y-4) by 252, based on (1).
You will get then instead of (2)
    252 + 2*(x-4) + 2*(y-4) = 380,   or
    2*(x-4) + 2*(y-4) = 380 - 252 = 128,
    (x-4) + (y-4) = 64.
So, the sum  (x-4) + (y-4) = 64,  while the product  (x-4)*(y-4) = 252.
Thus (x-4) and (y-4) are the roots of the quadratic equation  t^2 - 64t + 252 = 0.
Hence,    =   =   =   =  .
It gives  x-4 =  ,  x =   = 63.785 cm.
          y-4 =  ,  y =   =  8.215 cm.
CHECK.  Equation (1) : (x-4)*(y-4) = (63.785 -4)*(8.215-4) = 251.994 = 252 cm^2;
        Equation (2) : (x-4)*(y-4) + 2*(x-4) + 2*(y-4) = (63.785 -4)*(8.215-4) + 2*(63.785 -4) + 2*(8.215-4) = 379.994 = 380 cm^2.
ANSWER.  The dimensions are  x =   = 63.785 cm  and  y =   =  8.215 cm.
 
Solved.
 
 
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    - Making a box from a piece of cardboard 
 
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"Dimensions and the area of rectangles and circles and their elements".
 
 
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