SOLUTION: how much pure antifreeze must be added to 12L of a 40% solution of antifreeze to obtain a 60& solution?

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Question 115234This question is from textbook Algebra and trigonometry structure and method
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how much pure antifreeze must be added to 12L of a 40% solution of antifreeze to obtain a 60& solution? This question is from textbook Algebra and trigonometry structure and method

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
.4*12+1X=.6(12+X)
4.8+X=7.2+.6X
X-.6X=7.2-4.8
.4X=2.4
X=2.4/.4
X=6 LITERS OF PURE ANTIFREEZE MUST BE ADDED.
PROOF
.4*12+6=.6(12+6)
4.8+6=.6*18
10.8=10.8