Question 1152286:  Two dice are rolled. Find the probability of the event described. 
 
A) The score on the dice is no more than 7
 
 
B) The score on the dice is 7 
 
 Answer by rothauserc(4718)      (Show Source): 
You can  put this solution on YOUR website! Consider the event space for rolling 2 dice 
: 
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6) 
: 
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6) 
: 
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6) 
: 
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6) 
: 
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6) 
: 
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6) 
: 
There are 6 * 6 = 36 events in the event space for rolling two dice 
: 
A) The events no more than 7 are (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3), (5,1), (5,2), (6,1) 
: 
There are 21 events that are no more than 7, therefore 
: 
Probability (P) (sum of dice is no more than 7) = 21/36 = 7/12 
: 
B) The events where the sum is 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) 
: 
There are 6 events that are equal to 7, therefore 
: 
P (sum of dice is 7) = 6/36 = 1/6 
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