SOLUTION: O.k so I have this rational function f(x)=x^2-x-2/4x+8, I am having trouble finding the oblique asymptote. When I perform long division a began by factoring the denominator in the
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-> SOLUTION: O.k so I have this rational function f(x)=x^2-x-2/4x+8, I am having trouble finding the oblique asymptote. When I perform long division a began by factoring the denominator in the
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Question 1152278: O.k so I have this rational function f(x)=x^2-x-2/4x+8, I am having trouble finding the oblique asymptote. When I perform long division a began by factoring the denominator in the form 4(x+2) because I believe it needs to be in the form x-c. I then carry out the division like normal I end up with a quotient of x-3 with a remainder of 4. My question is what happens with the 4 that I factored in the divisor? When I check the equation for the slant asymptote in my calculator it does not match up. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! You take that x-3 and divide it by the 4 you factored out earlier. That gives you the right asymptote. It is messier, but you can also divide 4x+8 into the function and deal with fractions. You will get a slant asymptote of y=(1/4)x-(3/4), which is the same thing.
