SOLUTION: <pre>Using the properties of determinants and trigonometry identities, show that
|cos(x + x²) sin(x + x²) -cos(x + x²)|
|A| = |sin(x - x²) cos(x - x²) sin(x - x
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-> SOLUTION: <pre>Using the properties of determinants and trigonometry identities, show that
|cos(x + x²) sin(x + x²) -cos(x + x²)|
|A| = |sin(x - x²) cos(x - x²) sin(x - x
Log On
Let a = x + x²
Let b = x - x²
Expand about the bottom row:
Swap the terms in the first big parentheses so you'll recognize the identity:
Using identities for cos(a ± b)
Swapping the factors in the second term so you'll recognize the identity:
Since a = x + x² andb = x - x², a+b = 2x and a-b = 2x²
Using identity for sin(a + b),
Edwin