SOLUTION: Find three consecutive positive integers such that the product of the first and the second is 37 less than the square of the third. Thnakss!!

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Question 1152201: Find three consecutive positive integers such that the product of the first and the second is 37 less than the square of the third.
Thnakss!!
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Let the numbers are x,x%2B1,x%2B2
if the product of the first and the second is 37 less than the square of the third, we have
x%28x%2B1%29=%28x%2B2%29%5E2-37
x%5E2%2Bx=x%5E2%2B4x%2B4-37
cross%28x%5E2%29%2Bx=cross%28x%5E2%29%2B4x-33
x=4x-33
33=4x-x
33=3x
x=11

the numbers are: 11,12,13