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The word "WOODCOCK" has 8 letters.
Of them, letter "O" has the multiplicity of 3;
letter "C" has the multiplicity of 2;
the rest of the letters are unique.
Therefore, the number of all distinguishable permutations (they are also called "distinguishable arrangements") is
=
= 3360. ANSWER
8! counts the number of all possible permutations of 8 letters.
3! in the denominator stays to account for repeating letter "O".
2! in the denominator stays to account for repeating letter "C".
Solved, answered and explained.