SOLUTION: Among Coffee drinkers, men drink a mean of 3.2 cups per day, with a standard deviation of 0.8 cups. Assume the number of coffee dinks per day follows a normal distribution.
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-> SOLUTION: Among Coffee drinkers, men drink a mean of 3.2 cups per day, with a standard deviation of 0.8 cups. Assume the number of coffee dinks per day follows a normal distribution.
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Question 1151946: Among Coffee drinkers, men drink a mean of 3.2 cups per day, with a standard deviation of 0.8 cups. Assume the number of coffee dinks per day follows a normal distribution.
a. What proportion dink 2 cups per day or more?
B. What proportion drink no more than 4 cups per day?
c. If the top 5% of coffee drinkers are considered heavy coffee drinkers, what is the minimum number of ups per day consumed by a heavy coffee drinker? Hint find the 95th percentile.
You can put this solution on YOUR website! mean is 3.2 cups per day and standard deviation is 0.8 cups
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a. z-score(2) = (2 - 3.2)/0.8 = -1.5
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probability(P) associated with a z-score of -1.5 is 0.0668
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P (men who drink more than 2 cups per day) = 1 - 0.0668 = 0.9332 is approximately 0.93
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Proportion of men who drink more than 2 cups daily is 93/100
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b. z-score(4) = (4 - 3.2)/0.8 = 1.0
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P associated with a z-score of 1.0 is 0.8413 is approximately 0.84
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Proportion of men who drink less than 4 cups a day = 84/100 = 21/25
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c. In the table of z-values, a z-score associated with a P of 0.95 is 1.64
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(X - 3.2)/0.8 = 1.64
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X - 3.2 = 1.64 * 0.8 = 1.312
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X = 4.512 is approximately 5
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Minimum number of cups consumed by a heavy coffee drinker is 5 cups
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