SOLUTION: Researchers are interested in estimating the average level of some enzyme in a certain human population with some interval. A random sample of 10 individuals was taken and it was f
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Question 1151903: Researchers are interested in estimating the average level of some enzyme in a certain human population with some interval. A random sample of 10 individuals was taken and it was found that the mean level of enzyme computed from this sample is 22unit. Assume that the level of enzyme in underlying population is normally distributed with variance of 8unit2. Construct the 95% CI for the estimate of the unknown population mean and interpret the result. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 95%CI half-interval is z=1.96*sigma/sqrt(10); sigma is sqrt(V) or sqrt(8) unit
the half-interval is 1.96*sqrt(8)/sqrt(10)=1.75
The whole interval is mean +/- half-interval or (20.25, 23.75)units
