SOLUTION: Consider the function fx = x^ +6x - 2 1- Find h, the x-coordinate of the vertex of this parabola. 2 - Substitute the two whole number values immediately to the left and right o

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Consider the function fx = x^ +6x - 2 1- Find h, the x-coordinate of the vertex of this parabola. 2 - Substitute the two whole number values immediately to the left and right o      Log On


   



Question 115162This question is from textbook Blitzer College Algebra
: Consider the function fx = x^ +6x - 2
1- Find h, the x-coordinate of the vertex of this parabola.
2 - Substitute the two whole number values immediately to the left and right of h into the function to find the corresponding y. Fill in the table below. Make sure your x-values are in increasing order in your table.
x y


h=__

I do not comprehend the equation/function/graph thing......can someone give me a look at how to do problems like this? Thanks - I have 3 more like it to do this week.
This question is from textbook Blitzer College Algebra

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
1) the vertex lies on the axis of symmetry ___ the equation is x=-b/2a ___ x=-6/(2*1) ___ x=-3 ___ this is the h value

2) the two numbers to the left (less than) of h are -5 and -4
___ the two to the right (greater than) are -2 and -1
___ plug the numbers as x-values into f(x) and find the corresponding y-values ___ y IS f(x); same thing, different name
___ enter the values in the table