SOLUTION: If you deposit money today in an account that pays 4% annual interest, how long will it take to double your money?

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Question 1151563: If you deposit money today in an account that pays 4% annual interest, how long will it take to double your money?
Found 4 solutions by MathLover1, Theo, ikleyn, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

If you deposit money today in an account that pays 4% annual interest, how long will it take to double your money?
Compound interest formula:
A=P%281%2Bi%29%5En, where +P=initial investment, i=interest rate per period, A=amount after n periods
A%2FP=%281%2Bi%29%5En
For given problem:
n=periods(years)
A=2P, i=.04
2P=P%281%2B.04%29%5En
2=%281.04%29%5En
1.04%5En=2
take log of both sides
log%281.04%5En%29=log%282%29
n%2Alog%281.04%29=log%282%29
n=log%282%29%2Flog%281.04%29
n+17.7+years
ans: It will take 17 years and 8 months to double the deposit money


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
f = p * (1 + r) ^ n
f is the future value
p is the present value
r is the interest rate per time period
n is the number of time periods.

with annual compounding and f = 2 * p and r = .04, the formula becomes:
2 = (1 + .04) ^ n
take the natural log of both sides of this equation to get:
ln(2) = ln(1.04^n)
since ln(1.04^n) is equal to n * ln(1.04), this becomes:
ln(2) = n * ln(1.04)
divide both sides of this equation by ln(1.04) and solve for n to get:
n = ln(2) / ln(1.04) = 17.67298769
confirm by replacing n with that in the original equation to get:
f = (1 + .04) ^ 17.67298769
solve for f to get:
f = 2
this confirms the solution is correct.
the solution, assuming annual compounding, is equal to 17.67298769 years.

if you assume monthly compounding, the formula becomes:
2 = (1 + .04/12) ^ n
n becomes the number of months.
take the natural log of both sides of this equation to get:
ln(2) = ln((1+ .04/12) ^ n)
this becomes ln(2) = n * ln(1 + .04/12)
divide both sides of the equation by ln(1 + .04/12) to get:
ln(2) / ln(1 + .04/12) = n
solve for n to get n = 208.2905355
that's the number of months.
divide that by 12 to get number of years = 17.35754463

with monthly compoounding, the number of years to double the money is slightly less because monthly compounding gives a higher effective interest rate per year than annual compounding.

with annual compounding, the effective annual interest rate is .04.
with monthly compounding, the effective annual interest rate is (1 + .04/12) ^ 12 - 1 = .040741543.

that's the rate,
the percent is 100 times that.
.04 = 4%
.040741543 = 4.0741543%

Answer by ikleyn(52858) About Me  (Show Source):
You can put this solution on YOUR website!
.
By default, from the problem description we MUST assume that the account is compound, 
that the compound period is one year and that the annual rate is 4%.


    The condition DOES NOT LEAVE a room to make other assumptions.


I will not repeat calculations of the two other tutors for this case --- they are correct.


But the conclusion that they both make for the answer to be 17.7 years, is WRONG.


The correct answer is THIS:


    17 years period is not enough to double the deposited amount;

    the 18 years period is just enough.


/\/\/\/\/\/

Alan tries to correct me, but I do not agree with his correction.

The words  "an account  pays  4%  annual interest"  COVER all possible variations,  making them non-essentials.


Any other treatment / interpretation of the condition  (if possible)  is a harassment over the common sense.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The compounding period must be specified.
------
It's probably annually, but you must state that.
---
It could be monthly, daily, or continuously.
PS Do NOT trust a banker to give you information.