SOLUTION: A water balloon thrown vertically in the air reaches its peak height after 2 seconds. If its height, as a function of time, is given by h(t)=-16t^2+bt+6, then find the value of b.
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-> SOLUTION: A water balloon thrown vertically in the air reaches its peak height after 2 seconds. If its height, as a function of time, is given by h(t)=-16t^2+bt+6, then find the value of b.
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Question 1151497: A water balloon thrown vertically in the air reaches its peak height after 2 seconds. If its height, as a function of time, is given by h(t)=-16t^2+bt+6, then find the value of b. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A water balloon thrown vertically in the air reaches its peak height after 2 seconds.
If its height, as a function of time, is given by h(t)=-16t^2+bt+6, then find the value of b.
:
Using the axis of symmetry formula; t = -b/(2a) where = 2
:
-b = 2*-32
b = 64 ft per second
