SOLUTION: ax + by = 5 ax² + by² = 10 ax³ + by³ = 50 ax⁴ + by⁴ = 130 Find, 13(x + y - xy) - 120(a + b) = ?

Algebra ->  Matrices-and-determiminant -> SOLUTION: ax + by = 5 ax² + by² = 10 ax³ + by³ = 50 ax⁴ + by⁴ = 130 Find, 13(x + y - xy) - 120(a + b) = ?      Log On


   



Question 1151472: ax + by = 5
ax² + by² = 10
ax³ + by³ = 50
ax⁴ + by⁴ = 130
Find,
13(x + y - xy) - 120(a + b) = ?

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
There may be some trick that gives an easier way than to solve for all the
letters, but here it is that way: 


Solve the first two equations for a, by Cramer's rule:
system%28ax%5E%22%22+%2B+by%5E%22%22+=+5%2C%0D%0Aax%5E2+%2B+by%5E2+=+10%29

Solve the 2nd and 3rd equations for a, by Cramer's rule:
system%28ax%5E2+%2B+by%5E2+=+10%2C%0D%0Aax%5E3+%2B+by%5E3+=+50%29

Set the first and second values for a equal:

Multiply both sides by
%28x%28y-x%29%29%2F5
y-2=2%28y-5%29%2Fx
x%28y-2%29=2%28y-5%29
equation 1:    x=%282%28y-5%29%29%2F%28y-2%29
-----------------------------
Solve the 3rd and 4th equations for a, by Cramer's rule:
system%28ax%5E3+%2B+by%5E3+=+50%2C%0D%0Aax%5E4+%2B+by%5E4+=+130%29

Set the second and third values for a equal:

Multiply both sides by
%28x%5E2%28y-x%29%29%2F10%5E%22%22
y-3=%285y-13%29%2Fx
x%28y-3%29=5y-13
equation 2:    x=%285y-13%29%2F%28y-5%29
Set the values of x from equations 1 and 2 equal
%282%28y-5%29%29%2F%28y-2%29=%285y-13%29%2F%28y-5%29

2%28y-5%29%5E2=%28y-2%29%285y-13%29

2%28y%5E2-10y%2B25%29=5y%5E2-23y%2B26
2y%5E2-20y%2B50=5y%5E2-23y%2B26
0=3y%5E2-3y-24
0=y%5E2-y-8
y+=+%28-%28-1%29+%2B-+sqrt%28%28-1%29%5E2-4%281%29%28-8%29+%29%29%2F%282%281%29%29+
y+=+%281+%2B-+sqrt%281%2B32+%29%29%2F2+
y+=+%281+%2B-+sqrt%2833%29%29%2F2+

x and y cannot be equal because the first two given equations
would be inconsistent. For if they were equal, we'd have
ax%2Bbx=5
Nultiplying thru by x gives
ax%5E2%2Bbx%5E2=5x=50 or that would give x=10, not what we got for y.
Therefore by symmetry of x and y, one of them has the + sign and the
other has the minus sign. So we choose them so that

y+=+1%2F2+%2B+sqrt%2833%29%2F2+
and
x+=+1%2F2+-+sqrt%2833%29%2F2+

Since
a=%2810%5E%22%22%28y-5%29%29%2F%28x%5E2%28y-x%29%29%0D%0A%29
y-5=1%2F2+%2B+sqrt%2833%29%2F2-5=-9%2F2%2Bsqrt%2833%29%2F2, so
10%5E%22%22%28y-5%29=10%28-9%2F2%2Bsqrt%2833%29%2F2%29=-45%2B5sqrt%2833%29

y-x=%281%2F2+%2B+sqrt%2833%29%2F2%29-%281%2F2+-+sqrt%2833%29%2F2%29=sqrt%2833%29

, so
x%5E2%28y-x%29=%2817%2F2-sqrt%2833%29%2F2%29%28sqrt%2833%29%29=17sqrt%2833%29%2F2-33%2F2

Rationalizing the denominator we get
a=%285%2811+-+5sqrt%2833%29%29%29%2F176
By symmetry, or by substituting,
b=%285%2811+%2B+5sqrt%2833%29%29%29%2F176 

So

13%28x+%2B+y+-+xy%29+-+120%28a+%2B+b%29

 









13%281%2B8%29+-+120%28%2855+-+25sqrt%2833%29%2B+55+%2B+25sqrt%2833%29%29%2F176%29

13%289%29+-+120%28110%29%2F176%29

117+-+13200%2F176%29

117+-+75%29

42

Edwin