SOLUTION: Which equations have a corresponding graph identical to the graph of y=tan(x) A) y=cot((pi/2)-x) B) y=-tan(-x) C) y=-cot(x-(pi/2)) D) y=cot((pi/2)+x) E) none of these

Algebra ->  Trigonometry-basics -> SOLUTION: Which equations have a corresponding graph identical to the graph of y=tan(x) A) y=cot((pi/2)-x) B) y=-tan(-x) C) y=-cot(x-(pi/2)) D) y=cot((pi/2)+x) E) none of these      Log On


   



Question 1151368: Which equations have a corresponding graph identical to the graph of y=tan(x)
A) y=cot((pi/2)-x)
B) y=-tan(-x)
C) y=-cot(x-(pi/2))
D) y=cot((pi/2)+x)
E) none of these

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Use the following identity :tan+%28-x+%29=-+tan+%28x+%29
so, answer is:
B) y=tan%28x%29=-tan%28-x%29