SOLUTION: Which equations have a corresponding graph identical to the graph of y=sin(-x)
A) y=cos(x+(pi/2))
B) -y=sin(x)
C) y=cos(x-((3/2)pi))
D) y=cos(x-(pi/2))
E) y=sin(x-(2pi))
F) y
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Trigonometry-basics
-> SOLUTION: Which equations have a corresponding graph identical to the graph of y=sin(-x)
A) y=cos(x+(pi/2))
B) -y=sin(x)
C) y=cos(x-((3/2)pi))
D) y=cos(x-(pi/2))
E) y=sin(x-(2pi))
F) y
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Question 1151365: Which equations have a corresponding graph identical to the graph of y=sin(-x)
A) y=cos(x+(pi/2))
B) -y=sin(x)
C) y=cos(x-((3/2)pi))
D) y=cos(x-(pi/2))
E) y=sin(x-(2pi))
F) y=-sin(x)
D) none of these Answer by MathLover1(20850) (Show Source):
