SOLUTION: In 3 years, Susan will be three times as old as his daughter. Three years ago, the sum of their ages was 56. What is the daughter's age now?

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Question 1151350: In 3 years, Susan will be three times as old as his daughter. Three years ago, the sum of their ages was 56. What is the daughter's age now?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
m, Susan the mother
d, daughter

system%28m%2B3=3%28d%2B3%29%2C%28m-3%29%2B%28d-3%29=56%29

system%28m-3d=6%2Cm%2Bd=62%29

3d%2B6=62-d
2d=62-6
d=31-3
highlight%28d=28%29

Answer by ikleyn(52799) About Me  (Show Source):
You can put this solution on YOUR website!
.
In 3 years, Susan will be three times as old as highlight%28cross%28his%29%29 her daughter. Three years ago, the sum of their ages was 56.
What is the daughter's age now?
~~~~~~~~~~~~~~~~~~~~~~~

m, Susan the mother
d, daughter


From the description, you have this system of 2 equations


    m + 3 = 3*(d+3),      (1)

    (m-3) + (d-3) = 56.   (2)


From equation (1), express  m = 3d + 6  and substitute it into equation (2). You will get


    ((3d+6) - 3) + (d-3) = 56,

    4d                   = 56

      d                  = 56/4 = 14.


ANSWER.  The daughter is 14 years old now.

Solved.

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The solution and the answer by @josgarithmetic,  giving  28 years for the daughter,  is   W R O N G.

For your safety,  ignore it  (!)