Question 1151306: Five years ago, Ana was twice as old as Jamie was then. Fifteen years from now, Jamie will be as old as Ana was ten years ago. How old is Jamie now?
Please solve thanks!
Found 3 solutions by Edwin McCravy, josmiceli, ikleyn:
Answer by Edwin McCravy(20056)   (Show Source):
You can put this solution on YOUR website!
Five years ago, Ana was twice as old as Jamie was then.
A-5 = 2(J-5) Fifteen years from now, Jamie will be as old as Ana was ten years ago.J+15 = A-10
Simplify that system and solve it by substitution or elimination.
How old is Jamie now?
I won't tell you Jamie's age but Ana is 55.
Please solve thanks!
No, you have the equations. You solve.
Edwin
Answer by josmiceli(19441)  (Show Source):
Answer by ikleyn(52787)  (Show Source):
You can put this solution on YOUR website! .
You can easily solve the problem using systems of two equations.
Let A be Ana's age and J be the Jamie's age.
Then from the condition, you have this system of equations
A - 5 = 2*(J-5) (1)
A - 10 = J + 15. (2)
To solve it, express A = 2J - 10 + 5 = 2J - 5 from the first equation and then substitute it into the second equation.
You will get
(2J - 10) - 5 = J + 15,
2J - 15 = J + 15
2J - J = 15 + 15
J = 30.
ANSWER. Jamie is 30 years old; Ana is A = 2J-5 = 2*30-5 = 55 years old.
Solved.
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There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problems
- Selected age word problems from the archive
- Age problems for mental solution
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
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