Question 1151138: below is an infinite sequence 3 11 19 27 35 43 51 59 67 im trying to determine what the 37th number is? the formula 8n-5
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
Answer: 291
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Explanation:
The given sequence is 3, 11, 19, 27, 35, 43, 51, 59, 67
If we plugged in n = 1, then we get 8*n - 5 = 8*1 - 5 = 8 - 5 = 3
If we plugged in n = 2, then we get 8*n - 5 = 8*2 - 5 = 16 - 5 = 11
If we plugged in n = 3, then we get 8*n - 5 = 8*3 - 5 = 24 - 5 = 19
If we plugged in n = 4, then we get 8*n - 5 = 8*4 - 5 = 32 - 5 = 27
And so on
Plug in n = 37 to get the 37th term
8*n - 5 = 8*37 - 5 = 296 - 5 = 291
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