SOLUTION: David is traveling to airport to catch a flight. if he travels at speed of 30 mph, he is late by 13 minutes. if he travels at speed of 40 mph,he will arrive 7 minutes earlier than
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-> SOLUTION: David is traveling to airport to catch a flight. if he travels at speed of 30 mph, he is late by 13 minutes. if he travels at speed of 40 mph,he will arrive 7 minutes earlier than
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Question 1150906: David is traveling to airport to catch a flight. if he travels at speed of 30 mph, he is late by 13 minutes. if he travels at speed of 40 mph,he will arrive 7 minutes earlier than the scheduled departure time of the flight. what is the distance to the airport(in miles).
Let "d" be the distance to the airport.
Then the time from home to the destination point at 30 mph is hours.
The time from home to the destination point at 40 mph is hours.
The difference of these times is 13 minutes PLUS 7 minutes, or 20 minutes, which is of an hour.
It gives you this "time" equation
- = .
To solve it, multiply both sides by 120. You will get
4d - 3d = 40,
d = 40.
ANSWER. The distance to the airport is 40 miles.
Solved.
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Using "time" equation is the STANDARD method of solving such problems.
From my solution, learn on how to write, how to use and how to solve a "time" equation.