SOLUTION: The volume of liquid in a cylindrical tank with its axis parallel to the ground, with radius r, depth of liquid h, and length L is: Vol = L*(r^2*acos((r-h)/r) - (r-h)*sqrt(2rh - h

Algebra ->  Volume -> SOLUTION: The volume of liquid in a cylindrical tank with its axis parallel to the ground, with radius r, depth of liquid h, and length L is: Vol = L*(r^2*acos((r-h)/r) - (r-h)*sqrt(2rh - h      Log On


   

Question 1150884: The volume of liquid in a cylindrical tank with its axis parallel to the ground, with radius r, depth of liquid h, and length L is:
Vol = L*(r^2*acos((r-h)/r) - (r-h)*sqrt(2rh - h^2))
For h < r, solve for h.
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
There is no algebraic way to solve for h.  That's because h appears both in the
argument of a trig function (cosine) and also elsewhere (in a square root).  The
only way to solve such is when all the letters but h are given, and then only by
iterative means, which amounts to some educated trial and error process, which is
best done by technology.

Edwin