SOLUTION: Charles is four times as old as his daughter Nina.Eight years ago he was ten times as old as Nina. How old is Charles today?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Charles is four times as old as his daughter Nina.Eight years ago he was ten times as old as Nina. How old is Charles today?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1150851: Charles is four times as old as his daughter Nina.Eight years ago he was ten times as old as Nina. How old is Charles today?
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Charles is four times as old as his daughter Nina.
Charles=4Nina......eq.1
Eight years ago he was ten times as old as Nina.
Charles-8=10%28Nina-8%29
Charles-8=10Nina-80
Charles=10Nina-80%2B8
Charles=10Nina-72.......eq.2
from eq.1 and eq.2
4Nina=10Nina-72
72=10Nina-4Nina
72=6Nina
Nina=72%2F6
Nina=12..........Nina is 12 years old today
then
Charles=4Nina......eq.1
Charles=4%2A12
Charles=48......Charles is 48 years old today

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Charles is four times as old as his daughter Nina.Eight years ago he was ten times as old as Nina. How old is Charles today?
My 1st "let" statement is usually associated with the variable that's being sought. In other words, here I would say, "Let Charles' age be C."
But, this would involve FRACTIONS, and that's a topic that most would rather stay away from, you included, I'd assume! So, I'll go with Nina.
Let Nina's age be N
Then Charles' is 4N
We then get: 4N - 8 = 10(N - 8)
4N - 8 = 10N - 80
4N - 40N = - 80 + 8
- 6N = - 72
N, or Nina's age is: matrix%281%2C3%2C+%28-+72%29%2F%28-+6%29%2C+%22=%22%2C+12%29
Therefore, Charles is: highlight_green%28matrix%281%2C4%2C+4%2812%29%2C+%22=%22%2C+48%2C+years-old%29%29