SOLUTION: In certain right triangles √h^2-a^2 = 24, where h represents the length of the hypotenuse and a is the length of one of the legs. Find all possible ordered pairs (h,a), where h,

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: In certain right triangles √h^2-a^2 = 24, where h represents the length of the hypotenuse and a is the length of one of the legs. Find all possible ordered pairs (h,a), where h,       Log On


   



Question 1150663: In certain right triangles √h^2-a^2 = 24, where h represents the length of the hypotenuse and a is the length of one of the legs. Find all possible ordered pairs (h,a), where h, a ∈ N. Explain your reasoning thoroughly. By Spirit of Math.

Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


sqrt%28h%5E2-a%5E2%29=24

Square both sides:
h%5E2-a%5E2+=+24%5E2+=+576

Factor the left hand side:
%28h%2Ba%29%28h-a%29+=+576

(1) Write 576 in every possible way as the product of two integers.
(2) For each of those ways, determine h and a.
(3) Reject solutions for which h and a are not both integers.

Note if h and a are to both be integers, then (h+a) and (h-a) must be either both even or both odd.
   h+a  h-a   h    a
  -------------------
   576   1    X    X
   288   2   145  143
   192   3    X    X
   144   4    74   70
    96   6    51   45
    72   8    40   32
    64   9    X    X
    48  12    30   18
    36  16    26   10
    32  18    25    7

Solutions:

(h,a) = {(145,143), (74,70), (51,45), (40,32), (30,18), (26,10), (25,7)}


Answer by ikleyn(52890) About Me  (Show Source):
You can put this solution on YOUR website!
.

In my yesterday post

https://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.1150638.html

https://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.1150638.html

I gave absolutely clear and thorough instructions on how to solve this problem.


Happy learning (!) and happy solving (!) (!)