Question 1150542: the diagonals of quadrilateral efgh intersects at d(1,2) efgh has vertices at e(4,6) and f(-3,4) what must coordinates of g and h to ensure that efgh is a parallelogram
Answer by greenestamps(13200)   (Show Source):
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The diagonals of a parallelogram bisect each other. That means the distance and direction from one vertex to the intersection of the diagonals is the same as the distance and direction from the intersection of the diagonals to the opposite vertex.
From e(4,6) to d(1,2) is 3 units right and 4 units down, so from d to g is 3 units right and 4 units down, making the coordinates of g (1-3,2-4) = (-2,-2).
From f(-3,4) to d(1,2) is 4 units up and 2 units down, so from d to h is 4 units up and 2 units down, making the coordinates of h (1+4,2-2) = (5,0).
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