SOLUTION: An isosceles trapezoid ABCD is inscribed in a circle of radius r, as shown. If AB = 2, CD = 8, and AD = 5, then what is r? https://imgur.com/UzSX50C

Algebra ->  Finance -> SOLUTION: An isosceles trapezoid ABCD is inscribed in a circle of radius r, as shown. If AB = 2, CD = 8, and AD = 5, then what is r? https://imgur.com/UzSX50C      Log On


   



Question 1150431: An isosceles trapezoid ABCD is inscribed in a circle of radius r, as shown. If AB = 2, CD = 8, and AD = 5, then what is r?
https://imgur.com/UzSX50C

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!



We draw EF perpendicular to both bases of the trapezoid, bisecting the
trapezoid, which makes EA=1 and FD=4 



Next we draw AG parallel to EF, which divides FD into FG=1 and GD=3,
and by the Pythagorean theorem, AG=4 since triangle AGD is a 3-4-5
right triangle: 



Next, let's sketch in the circle the trapezoid is inscribed in, and
let its center be O, which is a point on EF.



Next we draw x and y axes, so that the CD is along the x-axis, and
EF is along the y-axis.  That makes the point A be (1,4), and D be (4,0),
Then the equation of the circle is 
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2,

Since O is on the y-axis, O's x-coordinate in h=0. Its y-coordinate is k.

So the equation of the circle is

x%5E2%2B%28y-k%29%5E2=r%5E2



The points A(1,4) and D(4,0) lie on the circle, so we substitute each
in the equation of the circle:

system%281%5E2%2B%284-k%29%5E2=r%5E2%2C4%5E2%2B%280-k%29%5E2=r%5E2%29

system%281%2B%284-k%29%5E2=r%5E2%2C16%2Bk%5E2=r%5E2%29

You finish.  Solve that system by substitution and get 

k+=+1%2F8

and

r+=+%285sqrt%2841%29%29%2F8

Edwin