SOLUTION: The sum of interior angles of a regular polygon is 24 times the size of the exterior angle.
a)Find the number of sides of the polygon.
b)Name the polygon.
Algebra ->
Polygons
-> SOLUTION: The sum of interior angles of a regular polygon is 24 times the size of the exterior angle.
a)Find the number of sides of the polygon.
b)Name the polygon.
Log On
Question 1150365: The sum of interior angles of a regular polygon is 24 times the size of the exterior angle.
a)Find the number of sides of the polygon.
b)Name the polygon. Answer by ikleyn(52897) (Show Source):
The problem says
180*(n-2) = 24*(360/n). (1)
Here "n" is the number of sides (vertices) of the polygon;
left side is the sum of interior angles; right side is 24 times the exterior angle.
Simplify equation (1). First step is to cancel the factor 180 in both sides.
n-2 = 24*(2/n)
n^2 - 2n = 48
n^2 - 2n - 48 = 0
(n-8)*(n+6) = 0.
Of the two roots, only positive root n= 8 makes sense.
ANSWER. Number of sides is 8. The polygon is a regular octagon.