SOLUTION: Prof. Okamoto selects 3 different students to report on 3 different current events. If there are 24 students in the class, in how many ways can Professor Okamoto make the selection

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Question 1150343: Prof. Okamoto selects 3 different students to report on 3 different current events. If there are 24 students in the class, in how many ways can Professor Okamoto make the selection?

Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
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He can select the 3 students in C(24,3) ways; then he can assign the 3 different current events to those 3 students in 3! ways.

C%2824%2C3%29%2A%283%21%29+=+2024%2A6+=+12144

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.

Since the students are different and distinguishable, and since the current events are different and distinguishable,


the total number possible selections is  24*23*22 = 12144.


    24 choices for the first current event;

    then 23 choices for the second current event;

    and, finally, 22 choices for the third current event.


This type of entities in Combinatorics is called "PERMUTATIONS".