SOLUTION: The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how man

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how man      Log On


   



Question 1150257: The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how many children were at the fair?
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
A+C=1000
10A+5C=7100
-10A-10C=-10000
-5C=-2900
C=580 children
A=420 adults

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how many children were at the fair?
Let number of adults be A, and number of children, C
Then we get: A + C = 1,000 ------ eq (i)
Also, 10A + 5C = 7,100_____5(2A + C) = 5(1,420)_____2A + C = 1,420 ----- eq (ii)
---- Subtracting eq (i) from eq (ii)
Subtract value of "A" from 1,000 to get the number of children.