SOLUTION: I'm not sure how to do this one. Can you please help me with it?
The length of a rectangle is 2 meters longer than the width. If the area is 10 square meters, find the rectang
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-> SOLUTION: I'm not sure how to do this one. Can you please help me with it?
The length of a rectangle is 2 meters longer than the width. If the area is 10 square meters, find the rectang
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Question 115021: I'm not sure how to do this one. Can you please help me with it?
The length of a rectangle is 2 meters longer than the width. If the area is 10 square meters, find the rectangle's dimensions. Round to the nearest tenth of a meter. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! L=W+2
10=L*W
10=(W+2)W
10=W^2+2W
W^2+2W-10=0
USING THE QUADRATIC EQUATION WE GET:
W=(-2+-SQRT[2^2-4*1*-10])/2*1
W=(-2+-SQRT[4+40])/2
W=(-2+-SQRT44)/2
W=(-2+-6.633)/2
W=-2+6.633)/2
W=4.633/2
W=2.3165 ANSWER FOR THE WIDTH.
L=2.3165+2=4.3165 ANSWER FOR THE LENGTH.
PROOF
2.3165*4.3165=10
10~10
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