SOLUTION: a fx and a bus is 30 km apart from each other their initial speed is 288 kph and 342 kph each. if the acceleration of the bus is 2.0 m/s^2 and 3.0 m/s^2 for the other vehicle. how

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Question 1150099: a fx and a bus is 30 km apart from each other their initial speed is 288 kph and 342 kph each. if the acceleration of the bus is 2.0 m/s^2 and 3.0 m/s^2 for the other vehicle. how long is sec before both vehicle meet if they're travelling on the same direction
Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
. 

Acceleration  of 1 m/s^2 changes the instantaneous velocity from 0 m/s to 3600 m/s, i.e. from 0 km/h to 36 km/h.



So, the acceleration of 2 m/s^2 changes the " fx "  instantaneous velocity (I don't know which vehicle it is) 

uniformly in time from 288 km/h to 288+72 = 360 km/h, with the average speed of  %28288%2B360%29%2F2 = 324 km/h.



Similarly, the acceleration of 3 m/s^2 changes the bus' instantaneous velocity 

uniformly in time from 342 km/h to 342+108 = 450 km/h, with the average speed of  %28342%2B450%29%2F2 = 396 km/h.


In the given problem, it is ACCEPTABLE to replace accelerated moves by uniform moves with averaged speeds.


Therefore, the answer to the problem's question is  30%2F%28396-324%29 = 30%2F72 = 5%2F12 of an hour = 25 minutes.   ANSWER

SOLVED.