Question 1150008: A florist designs two high-profit arrangements— a funeral wreath and a bridal centerpiece. The company’s employees can complete up to 15 arrangements each day using up to 24 total person-hours of labor. It takes 4 person-hours to complete 1 funeral wreath, and 1 person-hour to complete 1 bridal centerpiece. How many of each type of arrangements should the florist produce daily for maximum profit, if the profit on a funeral wreath is $60 and the profit on a bridal centerpiece is $48?
Number of bridal centerpieces
Number of funeral wreaths
Found 2 solutions by Theo, ikleyn: Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! there's a couple of ways you can solve this.
you can do it graphically, or .....
you can use the following linear programming simplex method tool.
https://www.zweigmedia.com/RealWorld/simplex.html
the results using the tool are shown below.
the objective function is p = 60x + 48y
the constraints are:
x + y <= 15
this is because no more than 15 arrangements of any type can be made per day.
4x + y <= 24
this is because a maximum of 24 person hours can be expended each day and it takes 4 person hours to complete a funeral wreath and 1 person hour to complete a bridal centerpiece.
implied is that both x and y have to be greater than or equal to 0.
the simplex method tool tells you that the maximum profit is made when 3 funeral wreaths are produced and sold, and when 12 bridal centerpieces are produced and sold.
that's x = 3 and y = 12.
note that all the constraints are met.
x + y <= 15 (total arrangements <= 15)
4x + y <= 24 (total person hours <= 24)
the maximum profit is 3 * 60 + 12 * 48 = 756.
the tool was constrained to an integer solution because partial wreaths or centerpieces were not a consideration.
the result using the graphical method is shown below.
in this graph, the opposite of the constraints were graphed.
x + y <= 15 became x + y >= 15
4x + y <= 24 became 4x + y >= 24
x >= 0 became x <= 0
y >= 0 became y <= 0
the area of the graph that was NOT shaded became the region of feasibility.
the corner points of this region contained the maximum profit solution.
the profit at the point (0,15) was 60 * 0 + 48 * 15 = 720
the profit at the point (5.5,0) was 60 * 5.5 + 48 * 0 = 330
the profit at the point (2.333,12.667) was 60 * 2.333 + 48 * 12.667 = 747.996.
the problem with the graphical solution is that the solution needed to be integers, so some adjustment had to be made.
the maximum solution appeared to be (2.333,12.667).
these figures needed to be integers.
they had to satisfy the constraint, which were:
x + y <= 15
4x + y <= 24
if we rounded 2.333 to 2 and 12.667 to 13, then x + y <= 15 was satisfied (2 + 13 = 15) and 4x + y <= 24 was also satisfied (8 + 13 = 21).
the profit would be 60 * 2 + 48 * 13 = 744
if we rounded 2.333 to 3 and 12.667 to 12, then x + y <= 15 was satisfied (3 + 12 = 15) and 4x + y <= 24 was also satisfied (12 + 12 = 24).
the profit would be 60 * 3 + 48 * 12 = 756
the maximum profit was 756.
this agreed with the linear programming simplex method tool result.
your maximum profit is attained when 3 wreaths are built and sold, and when 12 center pieces are built and sold.
the graphing tool used was at https://www.desmos.com/calculator
Answer by ikleyn(52884) (Show Source):
You can put this solution on YOUR website! .
It seems strange to me how @Theo presented his solution.
So, I came to solve the problem and to present it in the way in how it SHOULD BE done.
Let x = # funeral wreath,
y = # bridal centerpieces.
The profit function (which is the objective function in this problem) is
F(x,y) = 60x + 48y dollars.
The restrictions are
x + y <= 15 (arrangements)
4x + y <= 24 (person-hours)
x >= 0, y >= 0.
The feasible region is shown in the Figure below.
Lines x + y = 15 (red) and 4x + y = 24
The feasible region is the quadrilateral in QI, under the green and the red lines.
It has vertices
P1 = (0,0)
P2 = (0,15) y-intercept of red line;
P3 = (3,12) intersection of red and green lines
P4 = (6,0) x-intercept of green line.
The values of the objective function at the vertices are
P1 : F(0,0) = 60*0 + 48*0 = 0;
P2 : F(0,15) = 60*0 + 48*15 = 720;
P3 : F(3,12) = 60*3 + 48*12 = 756;
P4 : F(15,0) = 60*5 + 48*0 = 300.
The maximum value of the objective function (of the profit) is achieved at point P3.
Hence, this point gives the solution to the problem.
The maximum profit is achieved if the company produces 3 funeral wreath and 12 bridal centerpieces per day.
The maximum profit then is 756 dollars.
Solved.
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To see other similar problems solved by the Linear Programming method, look into the lesson
- Solving minimax problems by the Linear Programming method
in this site.
Also, look into the solutions of other similar problems in the archive to this forum under the links
https://www.algebra.com/algebra/homework/Linear-equations/Linear-equations.faq.question.1148776.html
https://www.algebra.com/algebra/homework/Inequalities/Inequalities.faq.question.1142000.html
https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.1137172.html
https://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.1136382.html
https://www.algebra.com/algebra/homework/Coordinate-system/Coordinate-system.faq.question.1134444.html
https://www.algebra.com/algebra/homework/Graphs/Graphs.faq.question.1131906.html
https://www.algebra.com/algebra/homework/coordinate/word/Linear_Equations_And_Systems_Word_Problems.faq.question.1131043.html
https://www.algebra.com/algebra/homework/word/finance/Money_Word_Problems.faq.question.1129285.html
https://www.algebra.com/algebra/homework/playground/test.faq.question.1112482.html
https://www.algebra.com/algebra/homework/Finance/Finance.faq.question.1102103.html
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