SOLUTION: Directions: use the given zero to find the remaining zeros of the function. f(x)=x^3-2x^2+36x-72; zero: 6i

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Directions: use the given zero to find the remaining zeros of the function. f(x)=x^3-2x^2+36x-72; zero: 6i      Log On


   

Question 1150006: Directions: use the given zero to find the remaining zeros of the function.
f(x)=x^3-2x^2+36x-72; zero: 6i
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Other complex zero is -6i.

%28x%2B6i%29%28x-6i%29
x%5E2-%286i%29%5E2
x%5E2%2B36


Notice your expression for f(x) is factorable.
x%5E3-2x%5E2%2B36x-72
x%5E3%2B36x-2x%5E2-72
x%28x%5E2%2B36%29-2%28x%5E2%2B36%29
%28x%5E2%2B36%29%28x-2%29
Other zero is highlight_green%282%29.