SOLUTION: (1 point) How much do you need to invest in an account earning an annual interest rate of 2.233% compounded weekly, so that your money will grow to $7,230.00 in 36 weeks? 7230

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Question 1149944: (1 point) How much do you need to invest in an account earning an annual interest rate of 2.233% compounded weekly, so that your money will grow to $7,230.00 in 36 weeks?

7230=P(1+.02233/52)^52(?) I'm not sure what to put for t

Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the length of time was 10 years, then +t+=+10+
so, if the time is 36 weeks, then +t+=+36%2F52+
------------------
+7230+=+P%2A%28+1+%2B+.02233%2F52+%29%5E%28+52%2A%2836%2F52%29+%29+
+7230+=+P%2A%28+1+%2B+.000429+%29%5E36+
+7230+=+P%2A1.015576+
+P+=+7119.11+
$7,119.11
Get another opinion if needed

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
(1 point) How much do you need to invest in an account earning an annual interest rate of 2.233% compounded weekly, so that your money will grow to $7,230.00 in 36 weeks?
7230=P(1+.02233/52)^52(?) I'm not sure what to put for t
I'm not sure if the amount is PER WEEK or a LUMP-SUM. Based on your calculation though, it appears to be a LUMP-SUM. 
Responding to your question, it should be
P, or PV/Amount to be invested, should be: highlight_green%28%22%247%2C119.11%22%29