SOLUTION: How many terms has an arithmetic {{{highlight(cross(progreression))}}} <U>progression</U> where sum is 1340 with first term 3 and nth term 131?
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Sequences-and-series
-> SOLUTION: How many terms has an arithmetic {{{highlight(cross(progreression))}}} <U>progression</U> where sum is 1340 with first term 3 and nth term 131?
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For any arithmetic progression of n terms , , . . . , the formula for its sum S works
S = .
In our case, it gives
1340 = = .
Hence,
n = = 2*10 = 20.
ANSWER. The number of the terms in the progression is 20.
