SOLUTION: Find the x-intercept(s) and the coordinates of the vertex for the parabola y = -x^2 - 2x - 1. If there is more than one -intercept, separate them with commas.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the x-intercept(s) and the coordinates of the vertex for the parabola y = -x^2 - 2x - 1. If there is more than one -intercept, separate them with commas.       Log On


   

Question 1149862: Find the x-intercept(s) and the coordinates of the vertex
for the parabola y = -x^2 - 2x - 1. If there is more than
one -intercept, separate them with commas.
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x-intercept(s) and the coordinates of the vertex for the parabola
y = -x^2 - 2x - 1. If there is more than one -intercept, separate them with commas.
y+=+-x%5E2+-+2x+-+1

x-intercepts:

-x%5E2-2x-1=0
x%5E2%2B2x%2B1=0
%28x%2B1%29%28x%2B1%29=0
x%2B1=0
x=-1

x-intercept = (-1,0)

-------------

x-coordinate of the vertex = -b%2F%282a%29=-%28-2%29%2F%282%28-1%29%29=-1

y-coordinate of the vertex =-x%5E2-2x-1=-%28-1%29%5E2-2%28-1%29-1+=+-1%2B2-1=0

vertex = (-1,0)

Whatd'y'know!!! The x-intercept and the vertex are the same point!!!

graph%28400%2C400%2C-4%2C3%2C-5%2C2%2C-x%5E2-2x-1%29

Edwin