.
The numbers of appropriate outcomes are as follows.
the sum of 8: (2,6), (3,5), (4,4), (5,3), (6,2) (5 outcomes)
the sum of 9: (3,6), (4,5), (5,4), (6,3) (4 outcomes)
the sum of 10: (4,6), (5,5), (6,4) (3 outcomes)
the sum of 11: (5,6), (6,5) (2 outcomes)
the sum of 12: (6,6) (1 outcome)
So, there are 5 + 4 + 3 + 2 + 1 = 15 outcomes with the sum greater than 7;
of them, only 5 outcomes are "favorable".
Therefore, the conditional probability under the question is P =
=
.
In this problem, you can consider 15 outcomes as your space of events and 5 outcomes as the set of "favorable" events.
Solved.
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To see many other similar problems solved, look into the lesson
- Rolling a pair of fair dice
in this site. Learn the subject from there once and for all.