SOLUTION: hi I need a help on this question. Can you please explain it
if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number?
Thanks
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-> SOLUTION: hi I need a help on this question. Can you please explain it
if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number?
Thanks
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Question 1149732: hi I need a help on this question. Can you please explain it
if you continue the pattern 2 0 1 8 2 0 1 8 2 0 1 8 what would be the 2018th number?
Thanks Answer by ikleyn(52787) (Show Source):
Your sequence is PERIODIC.
The major period is these 4 terms {2 0 1 8}.
Divide 2018 by 4 to find the number of periods before 2018-th term
= 504.5.
It means that there are 504 periods of 4 numbers before 2018-th term.
Exclude (mentally) these 504 periods. 504*4 = 2016.
Hence, the next two terms are 2 and 0 at 2017-th and 2018-th positions, respectively.
So, 0 is at the 2018-th position. ANSWER