SOLUTION: A car dealer stocks mid-size and full size cars on her lot, which holds 60 cars. On the average, she borrows $13,000 to purchase a mid-size car and $18,000 to purchase a full size

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A car dealer stocks mid-size and full size cars on her lot, which holds 60 cars. On the average, she borrows $13,000 to purchase a mid-size car and $18,000 to purchase a full size       Log On


   

Question 1149631: A car dealer stocks mid-size and full size cars on her lot, which holds 60 cars. On the average, she borrows $13,000 to purchase a mid-size car and $18,000 to purchase a full size car. How many cars of
each type could she stock if her total debt is 1 million. How many cars of each type could she stock if her total debt is 1 million? Set up and solve a system using either elimination or substitution.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


(1) The total number of cars is 60:

x%2By=60

(2) Her total debt of $1,000,000 for the cars on the lot is $13,000 for each mid-size car and $18,000 for each full size car:

13000x%2B18000y+=+1000000

You can choose the method for solving the pair of equations and answer the question.