SOLUTION: Phyllis invested 27000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7 percent per year. After one year the total interest

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Question 1149612: Phyllis invested 27000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7 percent per year. After one year the total interest earned on these investments was 1570 dollars. How much money did she invest at each rate?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


By the standard algebraic solution method....

Let x be the amount at 5%; then the amount at 7% is 27000-x. Then the total interest is 1570 dollars:

.05%28x%29%2B.07%2827000-x%29+=+1570
.05x%2B1890-.07x+=+1570
...

You can finish the solution by that method.

Here is a non-algebraic method for finding the answer to "mixture" problems like this that I find much easier and faster than that algebraic approach.

(1a) $27000 all at 5% would yield $1350 interest
(1b) the actual interest was $1570
(1c) $27000 all at 7% would yield $1890 interest

(2) The actual interest of $1570 is 220/540 = 11/27 of the way from $1350 to $1890. (If it helps, picture the three interest amounts on a number line. $1350 to $1570 is a difference of $220; $1350 to $1890 is a difference of $540. So $1570 is 220/540 of the way from $1350 to $1890.)

That means 11/27 of the investment was at the higher rate.

ANSWER: 11/27 of $27,000, or $11,000, at 7%; the other $16,000 at 5%.

CHECK: .07(11000)+.05(16000) = 770+800 = 1570