SOLUTION: Suppose that a character from a 1960 movie, is normally 180cm tall, but each succeeding minute he shrinks to 99% of his size of the previous minute.
a) How tall is he after 1 hour
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Exponential-and-logarithmic-functions
-> SOLUTION: Suppose that a character from a 1960 movie, is normally 180cm tall, but each succeeding minute he shrinks to 99% of his size of the previous minute.
a) How tall is he after 1 hour
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Question 1149576: Suppose that a character from a 1960 movie, is normally 180cm tall, but each succeeding minute he shrinks to 99% of his size of the previous minute.
a) How tall is he after 1 hour? After 2 hours?
b) How long will it take him to become 1 cm tall? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Suppose that a character from a 1960 movie, is normally 180cm tall, but each succeeding minute he shrinks to 99% of his size of the previous minute.
a) How tall is he after 1 hour
h(t) = 180*0.99^t ------ t in minutes
1 hour = 60 minutes
h(60) = 180*0.99^60 = ~ 98.488 cm
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After 2 hours?
h(120) = 180*0.99^120
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b) How long will it take him to become 1 cm tall?
h(t) = 180*0.99^t = 1
0.99^t = 1/180
t*ln(0.99) = ln(1/180)
t = ln(1/180)/ln(0.99) minutes
